12 gram CO(NH2)2 dilarutkan dalam 200 gr air. Tentukanlah titik beku dan titik didih jika Kb air=0,52°C dan Kf air=1,86°C (Mr CO(NH2)2=60)

wt = 12 gram
wp = 200 gram
Kb = 0,52
Kf = 1,86
Mr = 60
Tb = ...?
Tf = …?

m = wt/Mr x 1000/wp
= 12/60 x 1000/200
= 0,2 x 5
= 1 molal

∆Tb = m.Kb
= 1 x 0,52
= 0,52°C

Tb = Tb° + ∆Tb
= 100 + 0,52
= 100,52°C

∆Tf = m.Kf
= 1 x 1,86
= 1,86°C

Tf = Tf° - ∆Tf
= 0 - 1,86
= - 1,86°C