Matematika trigonometri ( saya minta tolong)
Matematika
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Pertanyaan
Matematika trigonometri ( saya minta tolong)
1 Jawaban
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1. Jawaban ahreumlim
Pi/6 = 30°
Pi/4 = 45°
Pi/3 = 60°
2Pi/3 = 120°
3Pi/4 = 135°
5Pi/6 = 150°
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a. sec(30°)
= 1/cos(30°)
= 1/ (√3/2)
= 2/√3
= 2√3 / 3
b. cot(30°)
= cos(30°) / sin(30°)
= (√3/2) / (1/2)
= √3
c. csc(120°)
= 1 / sin(120°)
= 1 / sin(180° - 60°)
= 1 / sin(60°)
= 1/ (√3 / 2)
= 2 / √3
= 2√3 / 3
d. tan(45°)
= sin(45°) / cos(45°)
= 1
e. sec(150°)
= 1/ cos(150°)
= 1 / cos(180° - 30°)
= 1 / -cos(30°)
= 1 / -(√3 / 2)
= - 2/√3
= - 2√3 / 3
f. cot(135°)
= cos(135°) / sin(135°)
= cos(180° - 45°) / sin(180° - 45°)
= -cos(45°) / sin(45°)
= -1
g. csc(60°)
= 1 / sin(60°)
= 1 / (√3 / 2)
= 2 / √3
= 2√3 / 3
h. tan(-30°)
= sin(-30°) / cos(-30°)
= - sin(30°) / cos(30°)
= (-1/2) / (√3 / 2)
= -1 / √3
= (-1/3)√3