jika g(x) = 2x - 1 dan (fog)(x) = 2 - 3x / x, x ≠ 0, maka invers fungsi f(x), yaitu f^-1(x) = tolong dijawab yah....

xjawab

g(x) = 2x - 1
fog(x) = (2 - 3x)/(x)
f{g(x)} = (2 -3x)/(x)
f(2x -1) = (2-3x)/(x)
f⁻¹ {(2 - 3x)/x } =  2x  -1

misalkan (2  -3x)/ x = y
xy = 2 - 3x
xy + 3x = 2
x(y+3) = 2
x = (2 )/(y+3

f⁻¹ (y) = 2 {2 / (y+3)} - 1
f⁻¹ (y) = 4/(y+3) - 1 =  (4 - y - 3)/(y+3)
f⁻¹ (x) =(-x + 1)/ (x + 3)