the value of x equation system y= x^2 - x - 6 and y = 2x -2 IS?

y = x² - x - 6
y = 2x - 2

2x - 2 = x² - x - 6
0 = x² - 3x - 4
0 = (x - 4)(x + 1)

x - 4 = 0
x = 4
or
x + 1 = 0
x = -1

Hp = {-1, 4}

System of Linear and Quadratic Equation.

x² - x - 6 = 2x - 2
x² - x - 6 - 2x + 2 = 0
x² - 3x - 4 = 0
(x - 4)(x + 1 = 0
x = 4 ∨ x = -1
The solution set is {(4, -1)}