1/x + 1/y = 5 2/x - 3/y = -5 dengan cara metode gabungan eliminasi dan substitusi

1/x + 1/y = 5
1/x = 5 - 1/y ... (i)

2/x - 3/y= -5 ... (ii)
Subtitusi (ii) ke (i)

2(5 - 1/y) - 3/y = -5
10 - 2/y - 3/y = -5
15 = 5/y
y = 5/15
y = 1/3

Subtitusi y = 1/3 ke (i)
1/x = 5 - 1 / (⅓)
1/x = 5 - 3
1/x = 2
x = ½

HP :{ ½ , ⅓ }