Matematika

Pertanyaan

9Log27+8Log4-2Log32=

2 Jawaban

  • 9log27+8log4-2log32
    (3/2)3log3+(2/3)2log2-(5/2)2log2
    3/2+2/3-5/2
    -1/3
  • Logaritma

    a'log a^n = n
    (a^n)'log b^m = m/n . a'log b

    ^ dibaca pangkat

    ••
    9'log 27 + 8'log 4 - 2'log 32
    = (3^2)'log 3^3 + (2^3)'log 2^2 - 2'log 2^5
    = 3/2 + 2/3 - 5
    = (9 + 4)/6 - 30/6
    = -17/6 ✔

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