tulang paha orang dewasa memiliki diameter 4 cm, jika tegangan tulang sebesar 700Mpa ,tulang paha akan patah jika mendapat gaya....N

P = F/A
P = 700 x 10^6
A = 3.14 x 2 x 2 x 10^(-4)
= 12.56 x 10^(-4)

F = P x A
700 x 10^6 x 12.56 x 10^-4
8792 x 100 = 879200 N

D1 d = 4cm r =2.10^-2
J = 700 Mpa
= 700.10^6 = 7.10^8 N/m
D2=F...?
D3 = F/A
F= J. A
7.10^8.Mr^-2
7.10^8.22/7.(2.10^-2)^2
(22.2.10^8.10^-4)^-1
44.10^-4
Sekiranya itu :)