Matematika

Pertanyaan

Tentukan hasil perkalian aljabar berikut

3x(2x^2 - 5y + 4) =
(3k - 4) (1 - 2k) =
(5m + 3) (4m^2 - m + 6) =
(3 - a) (3a + 4) (a-2) =

1 Jawaban

  • 3x(2x²-5y+4)= 6x³-15xy+12x= 2x³-5xy+4x

    (3k-4)(1-2k)= 3k-6k²-4+8k = -6k²+11k-4 = 6k²-11k+4

    (5m+3)(4m²-m+6)= 20m³-5m²+30m+12m²-3m+18 = 20m³+7m²+27m+18

    (3-a)(3a+4)(a-2)= 9a+12-3a²-4a (a-2) = 9a²+12a-3a³-4a²-18a-24+6a²+8a = -3a³+11a²+2a-24 = 3a³-11a²-2a+24

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