diketahui fungsi f(x)=x+5 dan g(x)=x²-25 tentukan lah fungsi berikut: 1.(f+g)(5) 2.(f-g)(x) 3.(f:g)(x) 4.(f×g)(-6)

Bab Fungsi
Matematika SMA Kelas X

1] (f + g) (x)
= x + 5 + x² - 25
= x² + x - 20

(f + g) (5)
= 5² + 5 - 20
= 25 + 5 - 20
= 10

2] (f - g) (x)
= (x + 5) - (x² - 25)
= x + 5 - x² + 25
= -x² + x + 30

3] (f : g) (x)
= (x + 5) : (x² - 25)
= (x + 5) : ((x + 5) (x - 5))
= 1/(x - 5)

4] (f x g) (x)
= (x + 5) (x² - 25)
= x^3 - 25x + 5x² - 125

(f x g) (-6)
= (-6)^4 - 25 . (-6) + 5 . (-6)² - 125
= 1.296 + 150 + 180 - 125
= 1.501

1.(f+g)(5) = (x+5) + (x2 - 25)
= (5+5) + (25-25)
= 10-0
= 10
2.(f-g)(x) = x2+x-20
3.(f:g)(x) = x+5 : x2-25
= x+5 : (x-5)(x+5)
= 1/(x-5)
4.(f.g)(-6) = (-6+5) . (36-25)
= -1 . 11
= -11