tolong ya jawab no 5 dan 6

[tex] \frac{AE}{AD}= \frac{BD-DC}{BD} [/tex]
[tex] \frac{10}{12}=  \frac{BD-6}{BD} [/tex]
10×BD = 12(BD-6)
10BD = 12BD-72
72 = 12BD-10BD
72 = 2BD
[tex] \frac{72}{2}[/tex] = BD
36 = BD

[tex] \frac{DE}{DA} = \frac{CD}{BD}[/tex]
[tex] \frac{14}{21} \frac{CD}{4+CD} [/tex]
14(4+CD) = 21×CD
56+14CD = 21CD
56 = 7CD
[tex] \frac{56}{7}[/tex] = CD
8 = CD