(5log49) × (7log25) = ... A.5 B.4 C.2 D.1 E.-2

5log49 x 7log25
2 x 5log7 x 2 x 7log5
4 x 5log7x7log5
4x1
4 (b)

LogAritMa

5'log 49 × 7'log 25
= 5'log 7² × 7'log 5²
= 2 . 5'log 7 × 2 . 7'log 5
= 2 × 2 × 5'log 7 . 7'log 5
= 4 × 1
= 4 ✔