Matematika

Pertanyaan

a) volume kerucut yang terpacung
a) volume kerucut yang terpacung

1 Jawaban

  • dit : a.volume kerucut =...
    b.LP kerucut=...
    c.LP kerucut la 21 cm

    jawab :

    s²=r²+t²=8² + 24² = 64 + 276 = √640 = 25.298

    V kerucut = ⅓ x π r² t
    = ⅓ x 22/7 x 7 x 24
    = ⅓ x 22 x 24
    = 22 x 8
    = 176 cm³

    Lp kerucut = π ( r + s )
    = 22/7 x 7 ( 7 + 25.298 cm )
    =556.556 cm

    Lp kerucut = ( Ia = 21 cm )
    = La x Ls
    = 21 x 556.556
    = 11,687.676 cm²

    NTAR KU CARI YG { B }