tentukan persamaan garis yang melalui titk (2,-3) & sejajar garis 2×-3y+5=0

Sejajar garis 2x-3y+5
m1=m2
m1 = -a/b
= -2/-3
= 2/3
m2=m1
m2= 2/3

Pers. garis yg melalui titik (2,-3) :
(y-y1) = m2(x-x1)
(y-(-3)) = 2/3(x-2)
y+3=2/3x-4/3
3(y+3) = 3(2/3x) - 3(4/3)
3y+9 = 2x - 4
-2x+3y+13 = 0
2x - 3y -13 = 0