integral 0 sampai 2 4x akar 4-x^2 dx

jawab

₀²∫ (4x) √(4 - x²) dx

u = 4 - x²
du = - 2x dx
4x dx = - 2 du

∫ -2 u^(1/2) du =
= -2 (2/3) U^(3/2) ]
= - 4/3 (4-x²) √(4-x²)]²₀
= -4/3 (0)
= 0