12 nP3 = 7 (n-1) P4, nilai n =
Matematika
mohonbantuan6
Pertanyaan
12 nP3 = 7 (n-1) P4, nilai n =
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1. Jawaban Anonyme
jawab
12 ( nP3) = 7 { (n-1) P4 }
12 .n ! / (n-3)! = 7 (n-1) ! / (n-1 -4)!
12 , n! / (n-3)! = 7 (n-1) ! / (n - 5 ) !
12 n! / (n- 1) ! = 7 (n-3)! / (n-5)!
12 n (n-1) ! / (n-1)! = 7 (n-3)(n-4)(n-5)! /(n-5)!
12 n= 7(n-3)(n-4)
12 n = 7 (n² -7n +12)
12 n = 7n² -49 n + 84
7n² - 49 n -12 n + 84 = 0
7n² - 61 n + 84 = 0
(7n - 12)(n -7) = 0
7n - 12 = 0 atau n - 7 = 0
n = 12/7 atau n = 7
n bilangan bulat , maka n = 7