Matematika

Pertanyaan

cos x=0,2 , x lancip tentukan sin(x-30)

1 Jawaban

  • jawab

    cos x = 0,2 = 2/10 = 1/5 = x/r
    y²  = r² - x²
    y² = 5² - 1²
    y² = 25-1= 24
    y =  √24 = 2√6
    sin x = y/r = 2√6 /(5)= 2/5  √6

    sin (x - 30) = sin x cos 30  - cos x sin 30
    = (2/5 √6)( 1/2 √3) - (1/5)(1/2)
    = 1/5 √18 - 1/10
    = 1/5 (3√2)  - 1/10
    = 3/5 √ 2 - 1/10
    = 1/10  (6 √2 - 1)

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