Matematika

Pertanyaan

Tentukan nilai
A. Log5+Log200-Log10=.........
B. 0.5Log1/8+3Log27-5Log1/125=.....

1 Jawaban

  • a.
    log5 + log200 - log 10 = log (5x200/10) = log 100 = log 10² = 2

    b.
    0,5log⅛ + ³log27 - 5log1/125
    = ½log½³ + ³log3³ - 5log5-³
    = 3 + 3 - 3
    = 3

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