kakak tolong jawab soal saya ya...

f(x) = 3(x - 1)² + 5
f(x) = 3(x² - 2x + 1) + 5
f(x) = 3x² - 6x + 3 + 5
f(x) = 3x² - 6x + 8

Format :
f(x) = ax² + bx + c
Maka
a = 3 , b = -6 , c = 8

a + b + c = 3 - 6 + 8 = 5

bentuk pers. kuadrat adalah
ax² + bx + c = 0

f(x) = 3(x-1)² + 5
f(x) = 3 (x² - 2x + 1) + 5
f(x) = 3x² - 6x + 3 + 5
f(x) = 3x² - 6x + 8

a = 3
b = -6
c = 8
jadi a + b + c
= 3 + (-6) + 8
= 5