Matematika

Pertanyaan

tolong dijawa yaa...... plisss cepat yaaaaaa
tolong dijawa  yaa...... plisss cepat yaaaaaa

1 Jawaban

  • 8([tex] \frac{1}{4} [/tex]p³ - 5p² + p - [tex] \frac{3}{2} [/tex]) + 6([tex] \frac{5}{3} [/tex] - p + 7p² - [tex] \frac{1}{2} [/tex]p³)
    =2p³ - 40p² + 8p - 12 + 10 - 6p + 42p² - 3p³
    =2p³ - 3p³ - 40p² + 42p² + 8p - 6p - 12 + 10
    =-p³ + 2p² + 2p - 2

    (7 - 3y - y²) - (2y² + 1)
    =7 - 3y - y² - 2y² - 1
    =7 - 1 - 3y - y² - 2y²
    =6 - 3y - 3y²