integral dari cos x / 1 - cos ^2 x

jawab

∫ cos x / (1- cos² x) dx =
= ∫ (cos x )/(sin² x) dx
= ∫ sin⁻² x . cos x dx
u = sin x
du = cos x dx
= ∫ u⁻² du
= - u⁻¹ + c
= - 1/ sin x + c
= - cosec x + c