Matematika

Pertanyaan

sin^2 x / 1 - sin^2 x = sec^2 x - 1
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1 Jawaban

  • jawab

    sin² x /(1- sin² x) =  sec² x  -1
    = (1 - cos² x) (cos² x)
    = (1/cos² x) - (cos² x / cos² x)
    = 1/ cos² x - 1
    = (1/cos x)² - 1
    = (sec x)²  - 1
    = sec²  -1

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