tolong banget jawabanya...

LogAritMa

²log (4^x + 12) = 3 + x
4^x + 12 = 2^(3 + x)
2^2x + 12 = 2^3 + 2^x
2^2x - 2^x + 12 - 8 = 0
(2^x)² - 2^x + 4 = 0
2^x1 . 2^x2 = c/a = 4/1 = 4
2^(x1 + x2) = 4
x1 + x2 = 2