Matematika

Pertanyaan

X+2y+3z=8
-x+y+3z=4
2x-y-z=-4

1 Jawaban

  • x+2y+3z = 8 ...(1)
    -x+y+3z = 4 ...(2)
    2x-y-z = -4 ...(3)
    eliminasi (1) dan (2)
    x+2y+3z = 8
    -x+y+3z = 4
    ___________-
    2x+y = 4 ...(4)
    eliminasi (2) dan (3)
    -x+y+3z = 4 |x1| -x+y+3z = 4
    2x-y-z = -4   |x3| 6x-3y-3z = -12
                               ____________+
                                5x-2y = -8 ...(5)
    eliminasi (4) dan (5)
    2x+y = 4     |x2| 4x+2y = 8
    5x+2y = -8  |x1| 5x+2y = -8
                             __________-
                                   -x = 16
                                    x = -16
    subtitusi (4)
    2x+y = 4
    2(-16)+y = 4
    -32+y = 4
    y = 4+32
    y = 36

    subtitusi (1)
    x+2y+3z = 8
    -16+2(36)+3z = 8
    -16+72+3z = 8
    56+3z = 8
    3z = 8-56
    3z = -48
    z = -48/3
    z = 16

    x = -16
    y = 36
    z = 16

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