Matematika

Pertanyaan

jawab donk jan dikacangin..jawab sebisanya ajaa
jawab donk jan dikacangin..jawab sebisanya ajaa

1 Jawaban

  • f(x) = 7 - 6x - x²

    • pembuat nol fungsi
    7 - 6x - x² = 0
    (7 + x)(1 - x) = 0
    x = -7 atau x = 1 ✔

    • persamaan sumbu simetri
    x = -b/2a = -(-6)/(2 . (-1)) = 6/-2 = -3
    x = -3 ✔

    • Koordinat titik balik maks
    x = -3
    f(-3) = 7 - 6(-3) - (-3)²
    y = 16

    Koordinat titik balik = (-3,16) ✔

    • daerah hasil
    daerah asal : -8 ≤ x ≤ 2
    f(x) = 7 - 6x - x²
    f(-8) = -9
    f(-3) = 16

    f(-3) = 16
    f(2) = -9

    Daerah hasil : -9 ≤ x ≤ 16, x e R