Turunan fungsi y=(2x-1)^3 (x2-3)^2
Matematika
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Pertanyaan
Turunan fungsi y=(2x-1)^3 (x2-3)^2
1 Jawaban
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1. Jawaban Anonyme
Derivatif.
y = uv → y' = u'v + uv'
y = (2x - 1)³ (x² - 3)²
y' = 3(2x - 1)²(2) (x² - 3)² + (2x - 1)³ 2(x² - 3)(2x)
= 6(2x - 1)²(x² - 3)² + 4x (2x - 1)³(x² - 3)
= (2x - 1)² [6(x² - 3)² + 4x (2x - 1)(x² - 3)]
= (2x - 1)² [6(x⁴ - 6x² + 9) + 4x(2x³ - 6x - x² + 3)]
= (2x - 1)² (14x⁴ - 4x³ - 60x² + 12x + 54)
= (2x - 1)² [2 (x + 1)(7x³ - 9x² - 21x + 27)]
= 2(2x - 1)² (x + 1) [x² (7x - 9) - 3(7x - 9)]
= 2(2x - 1)² (x + 1) (7x - 9)(x² - 3)
= 2(2x - 1)² (x² - 3)(x + 1)(7x - 9)